C does not have a "string" datatype. To create a string you have to use a char array or a char pointer. If you are not familur with char arrays I recomend that you read about them now.
To recap, a char pointer is defined like this:
main() { char *Text; } |
All this program does is reserve storage that will hold an address. At this point the address could be anything. To initalize Text you can code:
main() { char *Text = "Thunder"; } |
Text now has the address of the first character in Thunder. Graphically, things look like this.
(Address) (Data) ---- ---- | F1 | 00 <------- Text |----|----| (Data) (Adress) | F2 | 00 | ------------- |----|----| -------> 54 (T) | D1 | | F3 | 00 | | |--------|----| |----|----| *Text | | 68 (h) | D2 | | F4 | D1 | ------- |--------|----| --------- | 75 (u) | D3 | |--------|----| | 6E (n) | D4 | |--------|----| | 64 (d) | D5 | |--------|----| | 65 (e) | D6 | |--------|----| | 72 (r) | D7 | |--------|----| | 00 | D8 | -------------
Please note the 00 at the end of Thunder. This is the NULL character and is used to mark the end of a string.
If we wanted to O/P the data pointed to by a char pointer we can code.
Source |
main() { char *Text1 = "Thunder"; /* Define and initalize */ char *Text2; /* Define only */ Text2 = "Bird"; /* Point to some text */ printf("%s%s\n", Text1, Text2); } |
Result |
ThunderBird |
This is all very well, but there is a MAJOR problem! Thunder and Bird are constants, they cannot be changed in anyway. We need a method of pointing to some storage that can be altered and true to form, C provides a function called malloc to do just that.
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