PIC Microcontoller Radix Math Method

Binary to ASCII, 16 bit to 5 digits (1 at a time) no temp register (!)

by Nikolai Golovchenko

;Thanks Scott, your code is very instructive.
;Total execution time:
;worst case: 47 + 66 + 58 + 39 + 2 = 213 cycles(with known zero)
;worst case: 53 + 73 + 58 + 39 + 2 = 226 cycles(without known zero)

;Code size: 68

        clrf temp
sub30k
        movlw 3
        addwf temp, f
        movlw low(30000)
        subwf Lo, f

IFNDEF known_zero
        movlw high(30000)
        skpc
        movlw high(30000) + 1
        subwf Hi, f
ELSE
        rlf known_zero, w
        sublw high(30000) + 1
        subwf Hi, f
ENDIF
        skpnc
        goto sub30k

add10k
        decf temp, f
        movlw low(10000)
        addwf Lo, f

IFNDEF known_zero
        movlw high(10000)
        skpnc
        movlw high(10000) + 1
        addwf Hi, f
ELSE
        rlf known_zero, w
        addlw high(10000)
        addwf Hi, f
ENDIF
        skpc
        goto add10k
;       Output(temp)         ;output temp = TenK
;worst case: 10 * 3 + 9 * 3 - 1 = 47 (with known zero)
;worst case: 11 * 3 + 10 * 3 - 1 = 53 (without known zero)

        clrf temp
sub3k
        movlw 3
        addwf temp, f
        movlw low(3000)
        subwf Lo, f
IFNDEF known_zero
        movlw high(3000)
        skpc
        movlw high(3000) + 1
        subwf Hi, f
ELSE
        rlf known_zero, w
        sublw high(3000) + 1
        subwf Hi, f
ENDIF
        skpnc
        goto sub3k
add1k
        decf temp, f
        movlw low(1000)
        addwf Lo, f

IFNDEF known_zero
        movlw high(1000)
        skpnc
        movlw high(1000) + 1
        addwf Hi, f
ELSE
        rlf known_zero, w
        addlw high(1000)
        addwf Hi, f
ENDIF
        skpc
        goto add1k
;       Output(temp)         ;output temp = Thou
;worst case: 10 * 4 + 9 * 3 - 1 = 66 (with known zero)
;worst case: 11 * 4 + 10 * 3 - 1 = 73 (without known zero)

        clrf temp
sub300
        movlw 3
        addwf temp, f
        movlw low(300)
        subwf Lo, f
IFNDEF known_zero
        movlw high(300)
        skpc
        movlw high(300) + 1
        subwf Hi, f
ELSE
        rlf known_zero, w
        sublw high(300) + 1
        subwf Hi, f
ENDIF
        skpnc
        goto sub300
        movlw 100
add100
        decf temp, f
        addwf Lo, f
        skpc
        goto add100
        incf Hi, f
        btfsc Hi, 7
        goto add100
;       Output(temp)         ;output temp = Hund
;worst case: 10 * 4 + 5 * 3 + 3 = 59

        clrf temp
        movlw 30
sub30
        incf temp, f
        subwf Lo, f
        skpnc
        goto sub30
        movfw temp
        rlf temp, f
        addwf temp, f
        movlw 10
add10
        decf temp, f
        addwf Lo, f
        skpc
        goto add10
;       Output(temp)         ;output temp = Tens
;worst case: 5 * 4 + 5 * 3 + 4 = 39

;       Output(Lo)         ;output temp = Ones

Questions:

• TakeThisOuTmrken88-Remove- at gmail.com asks:

  I am new to PIC, so I apologise in advance for this question.
  
  I am trying to get the ten-bit number from a 16F877a's A/D convertor to a computer using Hyperterminal, so this code converts the binary ADC value into an ASCII decimal, I assume?
  
  I am using MPASM to programme the code, and understand the basics. What I do not understand is the numbers in brackets after movlw. Do I take out the "high"/"low" before it?
  
  Also, since the ADC is only 10-bit, can the first section of the code "Output(temp) ;output temp = TenK" be discarded?
  
  Thank you in advance!

  James Newton replies: If I remember correctly, high() takes the upper 8 bits of the value and low() takes only the lower 8 bits.

  Yes, you can safely remove the TenK output.+

  +

Comments:

• TakeThisOuTmrken88-Remove- at gmail.com

  Thank you for the reply!
  
  How about the Hi and Lo variables? I thought those two would be high and low bytes of the binary number...
  I assembled the unedited code with MPASM and it seemed to have assembled fine.
  
  My second question was not too clear; sorry! I meant whether I can take out the entire code from the beginning up to the TenK output. If I do that, would it affect the last four digits?
  
  Thank you very much!

  James Newton replies: Try it and see! Let us know the result? Ken of Operation Radiation replies: To answer my own question from a long time ago, it does not work. Anyways, the result is not actually in ASCII, but in decimal. One needs to add 0x30h or .48 to the output digits to obtain the ASCII result. Thank you Nikolai for the great code!+

  +

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